write the equation of a line perpendicular to 9x+8y=3 that passes through the point (8,-7). Type an equation using slope- intercept form or using the given point in point- slope form. use integers or simplified fractions for any numbers in the equation.
9x + 8y = 3 8y = -9x + 3 y = -9/8x + 3/8...slope here is -9/8. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the perpendicular slope is 8/9 (see how I flipped the slope and changed the sign)
y = mx + b slope(m) = 8/9 (8,-7)....x = 8 and y = -7 now we sub and find b, the y int -7 = 8/9(8) + b -7 = 64/9 + b -7 - 64/9 = b -63/9 - 64/9 = b -127/9 = b
