addi5doty addi5doty
  • 03-12-2020
  • Mathematics
contestada

Solve (y-4)^2+63=0 where y is a real number.

Respuesta :

Hrishii
Hrishii Hrishii
  • 03-12-2020

Answer:

[tex] y = 4 + 3 \sqrt{7} i[/tex]

Step-by-step explanation:

[tex](y-4)^2+63=0 \\ \\ (y-4)^2 = - 63 \\ \\ (y-4)= \sqrt{ - 63} \\ \\ y - 4 = 3 \sqrt{7} i \\ \\ y = 4 + 3 \sqrt{7} i[/tex]

Answer Link

Otras preguntas

Why did Americans accept the Constitution, with its strong national government and powerful executive, after, only a decade earlier, violently revolting against
In this excerpt from A Midsummer Night’s Dream, Theseus suggests that Hermia _____.
Para las clases de alemán y biología necesito a. la manzana. b. unos zapatos. c. una computadora
When the ball crosses the end line and the offensive team last touched the ball, the defensive team gets a _________. PLZ HELP IN 10 MIN
you have a large tank filled with 175 gallons of water the tank springs a leak and water is pouring out at rate of 5 gallons per minute write and graph a linear
Solve for L. p=2L+2w
NEED HELP ASAP Which of the following equations describe the line shown below? Check all that apply. A.y - 1 = -4(x + 6) B.y - 6 = -4(x + 1) C.y = -4x + 3 D
chemical released by T cells for direct cell killing
A device on a building that absorbs radiant energy from the sun is
What is required for reactants to form bonds?